D = 15 cm, Luas Lingkaran Tersebut Adalah...
[tex] \sf \: l = {r}^{2} \times \pi \\ \\ \sf \: l = ( \frac{15}{2} {)}^{2} \times \pi \\ \\ \sf \: l = {8}^{2} \times 3.14 \\ \\ \sf \: l = 64 \times 3.14 \\ \\ \bf \: l = 200.96 \: {cm}^{2} [/tex]
Jawaban:
diket : diameter = 15 cm
ditanya : luas?
Diameter =15cm
Jari-jari(r)=15 : 2
=7,5
r²= 7,5²
phi =56.25
=3.14
Luas lingakaran
Rumus:
[tex]\pi \times {r}^{2} [/tex]
Luas lingkaran=
3.14 x 56.25
=176.625
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